{"id":101,"date":"2026-10-03T11:35:12","date_gmt":"2026-10-03T10:35:12","guid":{"rendered":"https:\/\/wpcalc.com\/tr\/redoks-reaksiyonlarini-dengeleme-2\/"},"modified":"2026-10-03T11:35:12","modified_gmt":"2026-10-03T10:35:12","slug":"redoks-reaksiyonlarini-dengeleme-2","status":"publish","type":"post","link":"https:\/\/wpcalc.com\/tr\/kimya\/redoks-reaksiyonlarini-dengeleme-2\/","title":{"rendered":"Redoks Reaksiyonlar\u0131n\u0131 Dengeleme"},"content":{"rendered":"<section class=\"not-prose calculator-box\" aria-labelledby=\"calculator-title\"><div class=\"flex items-baseline sm:items-center justify-between gap-2 sm:gap-3\"><div class=\"flex flex-col sm:flex-row sm:items-center gap-2\"><span class=\"icon icon-calculator text-primary-700! text-base! dark:text-primary-300!\" aria-hidden=\"true\"><\/span><h2 id=\"calculator-title\" class=\"text-lg font-display font-bold\">Redoks Denkleminizi Dengeleyin<\/h2><\/div><div class=\"calcdash-favorite group\">\n  <button type=\"button\" class=\"favorite\" id=\"favorite\" data-favorite-id=\"101\" data-favorite-title=\"Redoks Reaksiyonlar\u0131n\u0131 Dengeleme\" data-favorite-url=\"https:\/\/wpcalc.com\/tr\/kimya\/redoks-reaksiyonlarini-dengeleme-2\/\" data-favorite-excerpt=\"Bir redoks denklemini, reaktanlar\u0131n\u0131 ve \u00fcr\u00fcnlerini iyonik y\u00fckleriyle birlikte girerek dengeleyin. Hesaplay\u0131c\u0131, hem atomlar\u0131 hem de y\u00fck\u00fc koruyan katsay\u0131lar\u0131 bulur.\" aria-label=\"Favorilere ekle\" data-favorite-icon=\"icon icon-chemistry-1\">\n    <span class=\"icon icon-shape-star-empty\" aria-hidden=\"true\"><\/span>\n  <\/button>\n  <div class=\"calcdash-favorite__tip\" aria-hidden=\"true\">\n   <span class=\"favorite-tooltip\" id=\"favorite-tooltip\"><\/span>\n  <\/div>\n  <span class=\"sr-only\" role=\"status\" id=\"favorite-status\"><\/span>\n<\/div><\/div><form action=\"https:\/\/wpcalc.com\/tr\/kimya\/redoks-reaksiyonlarini-dengeleme-2\/\" method=\"POST\" class=\"calculator\" id=\"calculator-101\" data-post=\"101\"><fieldset class=\"fieldset-input\"><legend class=\"sr-only\">Giri\u015f alanlar\u0131<\/legend><div class=\"field is-single\" id=\"input-1\"><label for=\"field-1\">Redoks tepkimesini girin<\/label><input type=\"text\" name=\"redoks_tepkimesini_girin\" id=\"field-1\" aria-describedby=\"calc-info-1\" placeholder=\"\u00f6rn. MnO4^- + Fe^2+ = Mn^2+ + Fe^3+\" step=\"any\" value=\"S^2- + I2 = I^- + S\"\/><small id=\"calc-info-1\">Y\u00fckler i\u00e7in ^, t\u00fcrleri ay\u0131rmak i\u00e7in +, tepkime oku i\u00e7in = kullan\u0131n. \u00d6rnek: Cr2O7^2- + H^+ + e^- = Cr^3+ + H2O<\/small><\/div><\/fieldset><div class=\"buttons\"><button type=\"submit\" data-text=\"Yeniden hesapla\" id=\"calculate-button\" data-post=\"101\">Hesapla<\/button><button type=\"reset\">S\u0131f\u0131rla<\/button><\/div><div class=\"field is-checkbox hidden!\" id=\"field-auto-calc\"><input type=\"checkbox\" id=\"auto-calc\"><label for=\"auto-calc\">Otomatik hesapla<\/label><small>Etkinle\u015ftirilirse, herhangi bir de\u011feri de\u011fi\u015ftirdi\u011finizde sonu\u00e7 otomatik olarak g\u00fcncellenir.<\/small><\/div><div class=\"fieldset-result is-hidden\" aria-labelledby=\"result-title\" aria-live=\"polite\" role=\"region\"> <h3 class=\"result-title bg-gradient-to-r from-primary-50 to-gray-50 dark:from-primary-900 dark:to-gray-800\" id=\"result-title\"><span class=\"icon icon-s-pulse\" aria-hidden=\"true\"><\/span> Sonu\u00e7lar\u0131n\u0131z<\/h3><div class=\"result-box\"><div class=\"field-result is-borderless\" id=\"output-1\"><span class=\"field-value\" id=\"result\"><\/span><button type=\"button\" class=\"copy-result\" data-tooltip=\"Sonucu kopyala\" aria-label=\"Sonucu kopyala\"><span class=\"copy-icon icon icon-document-copy\" aria-hidden=\"true\"><\/span><\/button><\/div><div class=\"field-result is-borderless\" id=\"output-2\"><span class=\"field-value\" id=\"message\"><\/span><button type=\"button\" class=\"copy-result\" data-tooltip=\"Sonucu kopyala\" aria-label=\"Sonucu kopyala\"><span class=\"copy-icon icon icon-document-copy\" aria-hidden=\"true\"><\/span><\/button><\/div><div class=\"field-result is-borderless\" id=\"output-3\"><span class=\"field-value\" id=\"codevalid\"><\/span><button type=\"button\" class=\"copy-result\" data-tooltip=\"Sonucu kopyala\" aria-label=\"Sonucu kopyala\"><span class=\"copy-icon icon icon-document-copy\" aria-hidden=\"true\"><\/span><\/button><\/div><\/div><div class=\"result-actions\"><button type=\"button\" class=\"copy-link\"><svg viewBox=\"0 0 20 20\" fill=\"currentColor\" aria-hidden=\"true\"><path d=\"M12.232 4.232a2.5 2.5 0 0 1 3.536 3.536l-1.225 1.224a.75.75 0 0 0 1.061 1.06l1.224-1.224a4 4 0 0 0-5.656-5.656l-3 3a4 4 0 0 0 .225 5.865.75.75 0 0 0 .977-1.138 2.5 2.5 0 0 1-.142-3.667l3-3Z\"\/><path d=\"M11.603 7.963a.75.75 0 0 0-.977 1.138 2.5 2.5 0 0 1 .142 3.667l-3 3a2.5 2.5 0 0 1-3.536-3.536l1.225-1.224a.75.75 0 0 0-1.061-1.06l-1.224 1.224a4 4 0 1 0 5.656 5.656l3-3a4 4 0 0 0-.225-5.865Z\"\/><\/svg><span class=\"copy-link__text\">Bu hesaplaman\u0131n ba\u011flant\u0131s\u0131n\u0131 kopyala<\/span><\/button><span class=\"sr-only\" role=\"status\" id=\"copy-link-status\"><\/span><\/div><\/div><a href=\"#respond\" class=\"hidden transition-opacity duration-300 opacity-0 w-50 text-sm justify-center items-center gap-2 px-4 py-2 rounded bg-gray-200 text-gray-700 hover:bg-gray-300\" id=\"leave-comment\"><span class=\"icon icon-comments\" aria-hidden=\"true\"><\/span>Yorum b\u0131rak<\/a><\/form><\/section><section id=\"calc-reactions\" class=\"not-prose hidden my-12 bg-gradient-to-r from-primary-50 to-gray-50 border border-indigo-100 rounded-xl px-6 py-4 shadow-sm\" data-post=\"101\" aria-live=\"polite\" aria-labelledby=\"calc-reactions-title\"><p id=\"calc-reactions-title\" class=\"text-sm text-gray-500 text-center mb-2\">Bu sonu\u00e7 hakk\u0131nda ne d\u00fc\u015f\u00fcn\u00fcyorsunuz?<\/p><div role=\"group\" aria-labelledby=\"calc-reactions-title\" class=\"grid grid-cols-3 sm:flex sm:flex-row sm:justify-around gap-4 sm:items-center sm:flex-wrap\"><button type=\"button\" aria-pressed=\"false\" class=\"reaction-btn flex flex-col items-center gap-1 text-sm text-gray-700 hover:text-primary-600 cursor-pointer transition-transform hover:scale-105\" data-reaction=\"like\"><span class=\"reaction-count\" data-reaction-count=\"like\">0<\/span><span class=\"reaction text-3xl\" aria-hidden=\"true\">\ud83d\ude00 <\/span><span class=\"reaction-description font-medium\">Be\u011fendim <\/span><\/button><button type=\"button\" aria-pressed=\"false\" class=\"reaction-btn flex flex-col items-center gap-1 text-sm text-gray-700 hover:text-primary-600 cursor-pointer transition-transform hover:scale-105\" data-reaction=\"helpful\"><span class=\"reaction-count\" data-reaction-count=\"helpful\">0<\/span><span class=\"reaction text-3xl\" aria-hidden=\"true\">\ud83d\udca1 <\/span><span class=\"reaction-description font-medium\">Faydal\u0131 <\/span><\/button><button type=\"button\" aria-pressed=\"false\" class=\"reaction-btn flex flex-col items-center gap-1 text-sm text-gray-700 hover:text-primary-600 cursor-pointer transition-transform hover:scale-105\" data-reaction=\"confused\"><span class=\"reaction-count\" data-reaction-count=\"confused\">0<\/span><span class=\"reaction text-3xl\" aria-hidden=\"true\">\ud83d\ude15 <\/span><span class=\"reaction-description font-medium\">Kafam kar\u0131\u015ft\u0131 <\/span><\/button><button type=\"button\" aria-pressed=\"false\" class=\"reaction-btn flex flex-col items-center gap-1 text-sm text-gray-700 hover:text-primary-600 cursor-pointer transition-transform hover:scale-105\" data-reaction=\"disappointed\"><span class=\"reaction-count\" data-reaction-count=\"disappointed\">0<\/span><span class=\"reaction text-3xl\" aria-hidden=\"true\">\ud83d\ude1e <\/span><span class=\"reaction-description font-medium\">Hayal k\u0131r\u0131kl\u0131\u011f\u0131 <\/span><\/button><button type=\"button\" aria-pressed=\"false\" class=\"reaction-btn flex flex-col items-center gap-1 text-sm text-gray-700 hover:text-primary-600 cursor-pointer transition-transform hover:scale-105\" data-reaction=\"inaccurate\"><span class=\"reaction-count\" data-reaction-count=\"inaccurate\">0<\/span><span class=\"reaction text-3xl\" aria-hidden=\"true\">\u274c <\/span><span class=\"reaction-description font-medium\">Hatal\u0131 <\/span><\/button><\/div><div id=\"reaction-message\" class=\"hidden mt-8 rounded-md border border-primary-100 bg-white\/50 backdrop-blur-sm px-4 py-2 text-sm text-center shadow-sm\"><\/div><\/section><div class=\"calcdash-ad not-prose calcdash-ad--calc_result calcdash-ad--in-article\"><ins class=\"adsbygoogle\" style=\"display:block\" data-ad-client=\"ca-pub-1721569815777345\" data-ad-slot=\"6317458308\" data-ad-layout=\"in-article\" data-ad-format=\"fluid\"><\/ins><script>(adsbygoogle = window.adsbygoogle || []).push({});<\/script><\/div>\n<style id=\"wpcoderpro-inline-1\">.formula-box {\r\n\tborder-bottom: none !important;\r\n}<\/style><section class=\"formula-box\" aria-labelledby=\"formula-title\">\r\n\t<div id=\"formula-title\" class=\"not-prose font-display mb-4\"><span class=\"icon icon-formula\" aria-hidden=\"true\"><\/span><h2>Redoks Reaksiyonlar\u0131n\u0131 Dengeleme Form\u00fcl\u00fc<\/h2><\/div>\r\n\t<figure class=\"not-prose formula\">\r\n\t\t<figcaption class=\"formula-title\">Form\u00fcl<\/figcaption>\r\n\t\t<div class=\"text-base text-gray-800\" id=\"formula\">\n\\[\\sum_{i\\in L}c_i n_{i,E}=\\sum_{j\\in R}c_j n_{j,E}\\quad\\text{her element }E\\text{ i\u00e7in}\\]\n\\[\\sum_{i\\in L}c_i q_i=\\sum_{j\\in R}c_j q_j\\]\n<\/div>\r\n\t<\/figure>\r\n\t<\/p>\n<p><strong>Burada:<\/strong><\/p>\n<ul>\n<li>\\(L\\) ve \\(R\\) \u2014 denkleme girilen reaktanlar ve \u00fcr\u00fcnler.<\/li>\n<li>\\(c_i\\) \u2014 bir t\u00fcr\u00fcn katsay\u0131s\u0131.<\/li>\n<li>\\(n_{i,E}\\) \u2014 o t\u00fcrdeki \\(E\\) elementinin atom say\u0131s\u0131.<\/li>\n<li>\\(q_i\\) \u2014 t\u00fcr\u00fcn i\u015faretli elektrik y\u00fck\u00fc.<\/li>\n<\/ul>\n<p>Dengeli bir denklemde her iki tarafta her atom t\u00fcr\u00fcnden ayn\u0131 say\u0131da ve toplam y\u00fck ayn\u0131d\u0131r. Hesaplay\u0131c\u0131, bu koruma ko\u015fullar\u0131n\u0131 girdi\u011finiz t\u00fcrlerin katsay\u0131lar\u0131 i\u00e7in \u00e7\u00f6zer.<\/p>\n<p>\r\n<\/section>\n<style id=\"wpcoderpro-inline-2\">.calculation-box {\r\n\tborder-bottom: none !important;\r\n}<\/style><section id=\"calculation\" class=\"calculation-box\" aria-labelledby=\"calculation-title\">\r\n\t<div id=\"calculation-title\" class=\"not-prose font-display\"><span class=\"icon icon-unordered-list\" aria-hidden=\"true\"><\/span><h2>Redoks Reaksiyonlar\u0131n\u0131 Dengeleme \u2013 Hesaplama \u00d6rne\u011fi<\/h2><\/div>\r\n\r\n<\/p>\n<p><strong>\u00d6rnek:<\/strong> hesaplay\u0131c\u0131n\u0131n varsay\u0131lan reaksiyonunu dengeleyin: <code>S^2- + I2 = I^- + S<\/code>. S\u00fclf\u00fcr, k\u00fck\u00fcrde d\u00f6n\u00fc\u015fmek i\u00e7in iki elektron kaybederken iyot, iyod\u00fcre d\u00f6n\u00fc\u015fmek i\u00e7in iki elektron kazan\u0131r.<\/p>\n<p>\\[\\begin{aligned}\\mathrm{S}^{2-}&amp;\\rightarrow\\mathrm{S}+2e^-\\\\\\mathrm{I}_2+2e^-&amp;\\rightarrow 2\\mathrm{I}^-\\end{aligned}\\]<\/p>\n<p>Bu iki de\u011fi\u015fimi toplad\u0131\u011f\u0131m\u0131zda elektronlar birbirini g\u00f6t\u00fcr\u00fcr. Her iki tarafta bir k\u00fck\u00fcrt atomu ve iki iyot atomu vard\u0131r; toplam y\u00fck her iki tarafta da \\(-2\\)'dir.<\/p>\n<p>\\[\\mathrm{S}^{2-}+\\mathrm{I}_2\\rightarrow 2\\mathrm{I}^-+\\mathrm{S}\\]<\/p>\n<p><strong>Sonu\u00e7:<\/strong> katsay\u0131lar, girilen s\u0131rayla 1, 1, 2 ve 1'dir.<\/p>\n<p>\n\r\n<\/section>\n<h2>Hesaplay\u0131c\u0131 nas\u0131l kullan\u0131l\u0131r<\/h2>\n<ol>\n<li><strong>Redoks reaksiyonunu girin<\/strong> alan\u0131na reaktanlar\u0131, bir e\u015fittir i\u015fareti ve \u00fcr\u00fcnleri yaz\u0131n. \u00d6rne\u011fin: <code>S^2- + I2 = I^- + S<\/code>.<\/li>\n<li>T\u00fcrler aras\u0131nda <code>+<\/code> ve reaksiyon oku yerine <code>=<\/code> kullan\u0131n. Atom say\u0131lar\u0131n\u0131 <code>I2<\/code> veya <code>H2O<\/code> gibi normal say\u0131larla yaz\u0131n.<\/li>\n<li>\u0130yonik y\u00fckleri, gerekirse b\u00fcy\u00fckl\u00fc\u011f\u00fc ve ard\u0131ndan i\u015faretin izledi\u011fi bir d\u00fczeltme i\u015fareti (^) ile yaz\u0131n: <code>Fe^2+<\/code>, <code>MnO4^-<\/code> veya <code>H^+<\/code>. Yar\u0131 reaksiyon dengelerken <code>e^-<\/code> girebilirsiniz.<\/li>\n<li>Hesaplamay\u0131 \u00e7al\u0131\u015ft\u0131r\u0131n ve dengeli denklemi okuyun. T\u00fcrlerin istedi\u011finiz reaksiyonla e\u015fle\u015fti\u011fini kontrol edin; sonucun alt\u0131ndaki herhangi bir ileti bir giri\u015f veya dengeleme sorunu bildirebilir.<\/li>\n<\/ol>\n<p>Gerekli t\u00fcm reaktan ve \u00fcr\u00fcnleri kendiniz girin. Bir reaksiyon su, hidrojen iyonlar\u0131 veya hidroksit iyonlar\u0131 gerektiriyorsa, hesaplamadan \u00f6nce bunlar\u0131 uygun tarafa ekleyin. \u00d6rne\u011fin, asidik bir permanganat reaksiyonu hem <code>H^+<\/code> hem de <code>H2O<\/code> gerektirebilir; hesaplay\u0131c\u0131 bunlar\u0131 otomatik olarak eklemez.<\/p>\n<h2>Dengeli bir redoks denklemi ne anlama gelir<\/h2>\n<p>Redoks reaksiyonu, kimyasal t\u00fcrler aras\u0131nda elektron aktar\u0131r. <strong>Oksidasyon<\/strong> elektron kayb\u0131, <strong>indirgenme<\/strong> ise elektron kazan\u0131m\u0131d\u0131r. Yukar\u0131daki \u00f6rnekte s\u00fclf\u00fcr k\u00fck\u00fcrde oksitlenmi\u015f, iyot ise iyod\u00fcre indirgenmi\u015ftir. Kaybedilen ve kazan\u0131lan elektronlar e\u015fit olmal\u0131d\u0131r; elektronlar nihai toplam denklemde g\u00f6r\u00fcnmese bile.<\/p>\n<p>Katsay\u0131lar reaksiyona giren t\u00fcrlerin g\u00f6reli miktarlar\u0131n\u0131 belirtir; bir t\u00fcr\u00fcn bile\u015fimini de\u011fi\u015ftirmezler. \u00d6rne\u011fin, \\(\\mathrm{I}^-\\) \u00f6ncesindeki 2 iki iyod\u00fcr iyonu anlam\u0131na gelirken, \\(\\mathrm{I}_2\\) i\u00e7indeki 2 her iyot molek\u00fcl\u00fcndeki iki iyot atomunu ifade eder. Atomlar\u0131n yan\u0131 s\u0131ra y\u00fck de dengelenmelidir: yaln\u0131zca atom say\u0131lar\u0131n\u0131n e\u015fle\u015fmesi bir iyonik denklemi hatal\u0131 b\u0131rakabilir.<\/p>\n<p>Hesaplay\u0131c\u0131, verdi\u011finiz form\u00fclleri ve y\u00fckleri kullanarak bu koruma kurallar\u0131n\u0131 sa\u011flayan katsay\u0131lar\u0131 bulur. Oksidasyon basamaklar\u0131n\u0131 belirlemez veya yar\u0131 reaksiyon ad\u0131mlar\u0131n\u0131 g\u00f6stermez. Yaln\u0131zca n\u00f6tr t\u00fcrler i\u00e7eren bir reaksiyon i\u00e7in bunun yerine <a href=\"https:\/\/wpcalc.com\/tr\/kimya\/kimyasal-denklemleri-dengeleme\/\">Kimyasal Denklem Dengeleyici<\/a>'yi kullan\u0131n. Bir denklem dengelendikten sonra katsay\u0131lar\u0131 mol oran\u0131 olarak kullanabilirsiniz; <a href=\"https:\/\/wpcalc.com\/tr\/kimya\/atom-mol-cevirici\/\">Atomlardan Mole Hesaplay\u0131c\u0131<\/a>, izleyen bir hesaplama i\u00e7in par\u00e7ac\u0131k say\u0131lar\u0131n\u0131 d\u00f6n\u00fc\u015ft\u00fcrmede yard\u0131mc\u0131 olabilir.<\/p>\n<h2>Varsay\u0131mlar ve pratik s\u0131n\u0131rlar<\/h2>\n<ul>\n<li><strong>Ortam\u0131 denklem \u00fczerinden belirtin.<\/strong> Hesaplay\u0131c\u0131 asidik veya bazik ko\u015fullar\u0131 alg\u0131lamaz. Uygun bir asidik denklem i\u00e7in \\(\\mathrm{H}^+\\) ve \\(\\mathrm{H}_2\\mathrm{O}\\), uygun bir bazik denklem i\u00e7in \\(\\mathrm{OH}^-\\) ve \\(\\mathrm{H}_2\\mathrm{O}\\) ekleyin.<\/li>\n<li><strong>Belirtilen giri\u015f bi\u00e7imini kullan\u0131n.<\/strong> Bi\u00e7imlendirilmi\u015f alt simge veya \u00fcst simgeler yerine d\u00fcz kimyasal form\u00fcller yaz\u0131n. \u0130ki taraf aras\u0131nda ok yerine <code>=<\/code> kullan\u0131n.<\/li>\n<li><strong>\u00d6nerilen kimyasay\u0131 kontrol edin.<\/strong> Dengeleme, girilen t\u00fcrler i\u00e7in korunumu do\u011frular; bir reaksiyonun ger\u00e7ekle\u015fti\u011fini veya \u00fcr\u00fcnlerin kimyasal olarak uygun oldu\u011funu kan\u0131tlayamaz.<\/li>\n<li><strong>Hatalar\u0131 t\u00fcr listesini kontrol ederek giderin.<\/strong> Eksik bir \u00fcr\u00fcn, hatal\u0131 bir y\u00fck veya birden fazla olas\u0131 katsay\u0131 k\u00fcmesine sahip bir denklem benzersiz bir sonucu engelleyebilir. Bu hesaplay\u0131c\u0131 iyonik redoks denklemleri i\u00e7in tasarlanm\u0131\u015ft\u0131r ve herhangi bir iyondan \u00f6nce girilen n\u00f6tr bir t\u00fcr\u00fc reddedebilir.<\/li>\n<\/ul>\n","protected":false},"excerpt":{"rendered":"<p>Bir redoks denklemini, reaktanlar\u0131n\u0131 ve \u00fcr\u00fcnlerini iyonik y\u00fckleriyle birlikte girerek dengeleyin. Hesaplay\u0131c\u0131, hem atomlar\u0131 hem de y\u00fck\u00fc koruyan katsay\u0131lar\u0131 bulur.<\/p>\n","protected":false},"author":3168,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_acf_changed":false,"footnotes":""},"categories":[3],"tags":[65],"class_list":["post-101","post","type-post","status-publish","format-standard","hentry","category-kimya","tag-reaksiyonlar"],"acf":[],"_links":{"self":[{"href":"https:\/\/wpcalc.com\/tr\/wp-json\/wp\/v2\/posts\/101","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/wpcalc.com\/tr\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/wpcalc.com\/tr\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/wpcalc.com\/tr\/wp-json\/wp\/v2\/users\/3168"}],"replies":[{"embeddable":true,"href":"https:\/\/wpcalc.com\/tr\/wp-json\/wp\/v2\/comments?post=101"}],"version-history":[{"count":3,"href":"https:\/\/wpcalc.com\/tr\/wp-json\/wp\/v2\/posts\/101\/revisions"}],"predecessor-version":[{"id":1640,"href":"https:\/\/wpcalc.com\/tr\/wp-json\/wp\/v2\/posts\/101\/revisions\/1640"}],"wp:attachment":[{"href":"https:\/\/wpcalc.com\/tr\/wp-json\/wp\/v2\/media?parent=101"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/wpcalc.com\/tr\/wp-json\/wp\/v2\/categories?post=101"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/wpcalc.com\/tr\/wp-json\/wp\/v2\/tags?post=101"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}