Electric Current Converter
Convert electric field strength between V/m, kV/m, N/C, V/cm, and statV/cm. Enter an electric field value, then select the units to convert from and to.
Convert Electric Current Between Units
Electric Field Strength Formula
Where:
- \(E_{\mathrm{from}}\) — the entered electric field value
- \(E_{\mathrm{to}}\) — the converted electric field value
- \(f_{\mathrm{from}}\) and \(f_{\mathrm{to}}\) — the calculator’s factors for the selected units, expressed relative to V/m
The calculator multiplies the entered value by its source-unit factor and divides by its target-unit factor. Its factors are 1 for V/m and N/C, 1,000 for kV/m, 100 for V/cm, and 299.792458 for statV/cm. The statV/cm factor is incorrect as a physical conversion; see the limitation below.
Electric Field Strength – Calculation Example
Example: convert the default value of 1,000 V/m to kV/m.
\[ E_{\mathrm{to}}=1{,}000\,\mathrm{V/m}\times\frac{1}{1{,}000}=1\,\mathrm{kV/m} \]
Result: 1,000 V/m equals 1 kV/m.
How to use the calculator
- Enter a nonnegative number in Electric field value. The default is 1,000.
- Choose the value’s current unit under From unit.
- Choose the unit you need under To unit.
- Read Converted Electric Field Strength. You can change either unit to compare another conversion.
The available choices are volts per meter (V/m), kilovolts per meter (kV/m), newtons per coulomb (N/C), statvolts per centimeter (statV/cm), and volts per centimeter (V/cm). For physically reliable conversions, use the V/m, kV/m, N/C, and V/cm choices. The calculator’s statV/cm conversions have a known factor error.
What electric field strength means
Electric field strength describes the electric force that a charged object would experience at a location, per unit of charge. Its SI unit, the newton per coulomb (N/C), follows from that definition. The volt per meter (V/m) is an equivalent SI unit: \(1\,\mathrm{N/C}=1\,\mathrm{V/m}\). You can therefore switch between N/C and V/m without changing the numerical value.
Volts per meter also describe the potential difference per distance in a uniform field. For example, a field of 1,000 V/m corresponds to a potential change of 1,000 V across one meter in the field’s direction. The same strength can be written as 1 kV/m or 10 V/cm. Choosing a unit that suits the scale of a problem can make the result easier to read without changing the field itself.
Electric field strength is not electric current. Current measures the rate at which charge flows and is expressed in amperes; this calculator neither accepts nor converts amperes. It also does not calculate the force on a particular charge. If you know the charge and need that force, the relationship is \(F=qE\); the resulting force can be converted with the Force converter.
Conversion reference
| Unit | Equivalent in V/m |
|---|---|
| 1 V/m | 1 V/m |
| 1 N/C | 1 V/m |
| 1 kV/m | 1,000 V/m |
| 1 V/cm | 100 V/m |
| 1 statV/cm | Approximately 29,979.2458 V/m physically; the calculator uses 299.792458 V/m |
The first four rows can be used as a quick check on a result. For instance, converting from V/cm to V/m multiplies the number by 100 because a meter contains 100 centimeters. Converting back divides it by 100. The statV/cm row shows both the physical equivalence and the different factor currently used by the calculator; they should not be treated as interchangeable.
Assumptions and limitations
Do not rely on the statV/cm result for a physical conversion. One statvolt is approximately 299.792458 volts, but one centimeter is 0.01 meter. Thus, \(1\,\mathrm{statV/cm}\approx29{,}979.2458\,\mathrm{V/m}\), not 299.792458 V/m. The calculator omits the additional factor of 100: converting from statV/cm produces a value 100 times too small, while converting to statV/cm produces a value 100 times too large. Use the physical equivalence above for work involving that unit.
The input accepts only nonnegative values, so it represents field magnitude rather than a signed component or a full vector direction. Converting units cannot determine the field around a particular object or account for changes across space. The displayed result is rounded to six decimal places; very small nonzero results may therefore appear as zero. Keep more precision in intermediate work when that matters.
An electric field and a magnetic field are different quantities, even when both appear in the same problem. For magnetic-field units, use the Magnetic Flux Density converter rather than treating those units as electric field units.
Frequently Asked Questions
How do I calculate electric field strength from voltage and distance?
For a uniform field, divide the voltage difference by the distance measured along the field: \(E=|\Delta V|/d\). For example, 12 V across a 2 mm gap gives \(12/0.002=6{,}000\,\mathrm{V/m}\). This estimate does not describe a field that varies substantially across the gap, such as near the edge of an electrode.
What is a normal or safe electric field strength?
There is no single normal or safe value; the answer depends on where the field is measured and whether it is static or changing over time. Dry air often breaks down at roughly \(3\,\mathrm{MV/m}\) under idealized conditions, but humidity, pressure, and electrode shape can change that value. Air breakdown is not a human-exposure safety limit.
How do I convert MV/m or kV/cm if those units are not listed?
Convert through V/m. Multiply MV/m by 1,000,000 or kV/cm by 100,000 to get V/m; divide by the same number to convert back. For example, \(0.5\,\mathrm{MV/m}=500{,}000\,\mathrm{V/m}=5\,\mathrm{kV/cm}\). Check both the voltage prefix and the distance unit: overlooking the centimeters-to-meters step causes a factor-of-100 error.
What does a negative electric field value mean?
A negative value describes direction relative to a chosen axis, not a negative field magnitude. If right is positive, \(-200\,\mathrm{V/m}\) means a field of \(200\,\mathrm{V/m}\) pointing left. Unit conversion changes the size of the number, not its direction; keep the minus sign separately when using this magnitude-only converter.
Does an electric field always produce an electric current?
No. An electric field can exist in an insulator or an open circuit without a sustained flow of charge. Current requires mobile charges and an available path, among other conditions. In a conducting material, an applied field can drive current, but its size also depends on the material and geometry; field strength alone cannot be converted to amperes.
Is the electric field inside a conductor always zero?
It is zero inside the bulk of an ideal conductor in electrostatic equilibrium: charges redistribute until the internal field cancels. That rule does not generally apply to a conductor carrying steady current. A resistive wire needs an internal electric field to drive charge through it, so specify whether the situation is electrostatic before assuming zero.
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