Active Earth Pressure
Calculate the Rankine active earth pressure on a retaining wall from the retained soil height, unit weight and friction angle. Enter H, γ and φ to get the active pressure coefficient Ka and the resultant lateral force Pa.
Rankine Active Earth Pressure on a Retaining Wall
Active Earth Pressure Formula
Where:
- \(K_a\) — active earth-pressure coefficient (dimensionless)
- \(\varphi\) — internal (effective) friction angle of the backfill
- \(\gamma\) — bulk unit weight of the backfill soil
- \(H\) — vertical height of retained soil behind the wall
- \(p_z\) — lateral pressure at depth \(z\) below the ground surface
- \(P_a\) — resultant lateral force per unit length of wall
These are the classical Rankine (1857) formulas for a vertical, frictionless wall retaining a cohesionless soil with a horizontal ground surface. The lateral pressure increases linearly with depth, so the pressure diagram is a triangle and the resultant force \(P_a\) acts at a height of \(H/3\) above the base of the wall.
Active Earth Pressure – Calculation Example
Example: a retaining wall holds back 3 m of granular backfill with a unit weight of 18 kN/m³ and a friction angle of 30°.
\[ K_a = \frac{1 - \sin 30^\circ}{1 + \sin 30^\circ} = \frac{1 - 0.5}{1 + 0.5} = 0.3333 \]
\[ P_a = \tfrac{1}{2} \times 18 \times 3^2 \times 0.3333 = 27 \ \text{kN/m} \]
Result: the active earth-pressure coefficient is \(K_a = 0.333\), and the resultant lateral force is 27 kN per metre run of wall, acting at \(H/3 = 1\) m above the base. The pressure at the base of the wall is \(\gamma H K_a = 18 \times 3 \times 0.3333 = 18\) kPa.
How to Use the Calculator
- Enter the Retained soil height (H) — the vertical height of soil behind the wall — and select its unit (m or ft).
- Enter the Soil unit weight (γ) of the backfill and choose kN/m³ or lb/ft³. Typical sands fall in 15–20 kN/m³, clays in 16–21 kN/m³.
- Enter the Internal friction angle (φ) in degrees. Loose sand is roughly 28–32°, dense sand 35–42°, gravel 35–45°.
- Read the Active earth-pressure coefficient (Ka) and the Resultant lateral force per unit wall length (Pa), together with the point of application and the base pressure.
What Is Active Earth Pressure?
Active earth pressure is the lateral push that a soil mass exerts on a retaining structure when the structure moves or rotates slightly away from the soil, allowing the soil to expand and mobilize its shear strength. This outward movement — typically only a few millimetres to a few hundredths of the wall height — is enough for a wedge of soil behind the wall to reach a limiting, "active" failure state. The word "active" refers to the soil actively pushing on the wall, and it is the smallest of the three classical lateral pressure states: active, at-rest and passive.
Rankine's theory derives the active pressure coefficient purely from the soil's friction angle, assuming the wall face is vertical and frictionless and the backfill surface is horizontal. Under these conditions the soil fails along a plane inclined at \(45^\circ + \varphi/2\) to the horizontal, and the ratio of horizontal to vertical stress at every depth equals \(K_a\). A lower friction angle gives a larger \(K_a\): at \(\varphi = 30^\circ\), \(K_a \approx 0.33\); at \(\varphi = 40^\circ\) it drops to about 0.22, which is why well-graded, freely draining granular backfill is strongly preferred behind walls.
The result \(P_a\) is a force per metre run of wall (kN/m), obtained by integrating the triangular pressure diagram over the height. It acts horizontally at one third of the wall height above the base — the centroid of the triangle. In stability checks this force drives sliding and overturning, so it is the key input for sizing the wall, its footing bearing pressure and any reinforcement. For the structural design of the wall stem as a bending member, the triangular pressure distribution can be treated like a linearly varying load on a cantilever; see the uniformly loaded beam calculator for the general bending relationships.
Assumptions, Limitations and Practical Tips
- Granular backfill only. Rankine's \(K_a\) assumes a cohesionless soil (\(c = 0\)). For cohesive soils, apparent cohesion temporarily reduces active pressure but can be unreliable long-term — use total-stress or more advanced analysis for clays.
- Vertical, frictionless wall and level backfill. Wall friction, a battered face or a sloping ground surface change \(K_a\); Coulomb's theory or the sloping-backfill form of Rankine's coefficient should be used instead.
- No water, no surcharge. Hydrostatic pressure behind the wall (e.g. from a blocked drain) adds \(\tfrac{1}{2}\gamma_w H^2\) and often governs the design — always provide drainage. Uniform surcharge \(q\) adds an extra \(K_a\, q\) to the pressure at every depth.
- Wall must be free to yield. Active pressure only develops if the wall can move outward a little. Rigid, braced or basement walls that cannot yield should be designed for the larger at-rest pressure.
- Check the base. The base pressure \(\gamma H K_a\) and the point of application \(H/3\) are what you need for overturning and sliding checks; the footing dimensions then determine the bearing pressure under the base.
- Seismic action. Under earthquake loading the lateral demand increases; the Mononobe–Okabe method extends this coefficient approach to pseudo-static conditions.
Once the wall geometry is fixed, reinforcement detailing follows: estimate the required steel area from the bending moment and check bar layout with the rebar spacing and count calculator and the rebar weight calculator.
Frequently Asked Questions
How do I calculate active earth pressure by hand without the calculator?
First find the coefficient: \(K_a = \frac{1 - \sin\varphi}{1 + \sin\varphi}\), or equivalently \(\tan^2(45^\circ - \varphi/2)\). Then compute the resultant force per metre of wall as \(P_a = \tfrac{1}{2}\gamma H^2 K_a\). For example, with \(\varphi = 35^\circ\), \(\gamma = 18\) kN/m³ and \(H = 4\) m: \(K_a \approx 0.271\) and \(P_a \approx 39\) kN/m acting at \(H/3 \approx 1.33\) m above the base. A pocket calculator with a sine function is all you need.
What is a normal or good value of Ka?
For typical granular backfills, \(K_a\) falls between about 0.20 and 0.40. Loose sand at \(\varphi = 30^\circ\) gives 0.33; dense sand at \(\varphi = 40^\circ\) gives 0.22; gravel at \(\varphi = 45^\circ\) gives 0.17. A lower Ka means less lateral thrust on the wall, which is why dense, free-draining granular material is the preferred backfill. If your result is above 0.5, your friction angle is likely too low or the soil is not suited to Rankine theory.
Can I use this calculator with US customary units (psf, pcf, lb/ft³)?
Yes. The calculator converts internally, but you can also work entirely in imperial units: enter \(H\) in ft, \(\gamma\) in lb/ft³ (pcf) and the result \(P_a\) comes out in lb/ft of wall, while the base pressure is in lb/ft² (psf). For example, \(\gamma = 115\) pcf, \(H = 10\) ft, \(\varphi = 32^\circ\) gives \(K_a \approx 0.307\) and \(P_a \approx 1766\) lb/ft. Just keep the unit system consistent — never mix pcf with metres.
What is the difference between active, at-rest and passive earth pressure?
They differ by how much the wall moves. Active pressure (this calculator) is the minimum case: the wall yields away from the soil slightly and the soil relaxes. At-rest pressure (\(K_0 \approx 1 - \sin\varphi\)) applies to rigid, unyielding walls such as basement walls braced by floors, and is typically 30–50% higher than active. Passive pressure is the resistance the soil offers when pushed against, e.g. in front of a buried footing toe; \(K_p = 1/K_a\) and it is much larger.
Does the calculator handle a sloping backfill, wall friction or cohesion?
No — it uses the classical Rankine case: vertical, frictionless wall, horizontal cohesionless backfill, no water. For a sloping backfill at angle \(\beta\), use the sloping-ground Rankine coefficient or Coulomb's theory. For wall friction or a battered face, use Coulomb's formula. For cohesive soils (clays, \(c > 0\)), apparent cohesion reduces the short-term pressure but can relax over time, so a long-term effective-stress analysis is required for reliable design.
What happens if water builds up behind the wall?
Water pressure can double or triple the lateral thrust and frequently governs failure cases. A full water column of height \(H\) adds a hydrostatic force of \(\tfrac{1}{2}\gamma_w H^2 \approx 5H^2\) kN/m (with \(\gamma_w = 9.81\) kN/m³), acting on top of the reduced soil pressure (use buoyant unit weight \(\gamma' = \gamma - \gamma_w\) below the water table). This is why codes require drainage gravel, weep holes or geocomposite drains behind retaining walls — always design the drainage, not just the wall.
Where does the resultant force Pa act, and why H/3?
The active pressure diagram is a triangle, zero at the surface and maximum (\(\gamma H K_a\)) at the base. The resultant of a triangular load passes through its centroid, which lies at one third of the height above the base (\(H/3\)). This point of application matters for overturning checks: the overturning moment about the toe is \(P_a \times H/3\). A common mistake is assuming the force acts at mid-height \(H/2\), which underestimates the moment.